How many peptide fragments can be generated from the complete digestion of the polypeptide AGRCDKCQANRSLMNF with trypsin?
How many peptide fragments can be generated from the complete digestion of the polypeptide AGRCDKCQANRSLMNF with trypsin?
Select an option to attempt
Correct Answer: Option B
Explanation
Trypsin cleaves specifically after Arg (R) and Lys (K). Mapping the sequence AGRCDKCQANRSLMNF: Position 3 = R → cleaves after R: fragment 1 = AGR. Position 7 = K → cleaves after K: fragment 2 = CDKC. Wait — C is at pos 4, D at 5, K at 7. So: AGR | CDK | CQANR | SLMNF. Actually: A-G-R(3)-C-D-K(6)-C-Q-A-N-R(11)-S-L-M-N-F(16). Cuts after R(3), K(6), R(11) → 4 fragments: AGR | CDK | CQANR | SLMNF. Total = 4 peptide fragments.