If you mixed 20 mL of 50 mM sodium acetate (NaOAc) with 30 mL of 25 mM glucose, what would be the concentration of each in the final solution?
If you mixed 20 mL of 50 mM sodium acetate (NaOAc) with 30 mL of 25 mM glucose, what would be the concentration of each in the final solution?
Select an option to attempt
Correct Answer: Option B
Explanation
Mixing solutions — concentration after combining:Using conservation of moles: moles = concentration × volume, and final concentration = moles ÷ total volume.Final volume = 20 mL + 30 mL = 50 mL• NaOAc:• Glucose:Note: NaOAc and glucose are in separate solutions being mixed; they do not chemically interact. The calculation is a simple dilution for each component independently.Answer: 20 mM NaOAc, 15 mM Glucose (Option 2).